939. The square of the sum
Find the square
of the sum of the digits of a two-digit positive
integer.
Input. One two-digit positive integer n.
Output. Print the
square of the
sum
of the digits of the number n.
|
Sample
input |
Sample output |
|
23 |
25 |
SOLUTION
mathematics
Algorithm analysis
Let n = 
be a two-digit input number. Find its digits of tens a and
ones b:
·
a = n / 10;
·
b = n % 10.
Then the square
of the sum of digits of number n will be the
value of (a + b)2.
Algorithm realization
Read the value of n. Find the number of tens a and the
number of ones b.
scanf("%d",&n);
a = n / 10;
b = n % 10;
Compute and print the answer.
res = (a + b) *
(a + b);
printf("%d\n",res);
Algorithm realization with formatted input
#include <stdio.h>
int a, b, res;
int main(void)
{
scanf("%1d%1d",&a,&b);
res = (a + b) * (a + b);
printf("%d\n",res);
return 0;
}
Algorithm realization – string
#include <stdio.h>
char s[100];
int a, b, res;
int main(void)
{
gets(s);
a = s[0] - '0';
b = s[1] - '0';
res = (a + b) * (a + b);
printf("%d\n",res);
return 0;
}
Algorithm realization – STL
#include <iostream>
using namespace
std;
int n, a, b, res;
int main(void)
{
cin >> n;
a = n / 10; b = n % 10;
res =
(a + b) * (a + b);
cout << res << endl;
return 0;
}
Java realization
import java.util.*;
public class Main
{
public static void main(String []args)
{
Scanner con = new Scanner(System.in);
int n = con.nextInt();
int a = n / 10, b = n % 10;
int res = (a + b) * (a + b);
System.out.println(res);
}
}
Java realization – read a line
import java.util.*;
public class Main
{
public static void main(String []args)
{
Scanner con = new Scanner(System.in);
String s = con.nextLine();
int a = s.charAt(0)
- '0', b = s.charAt(1) - '0';
int res = (a + b) * (a + b);
System.out.println(res);
}
}
Python realization
n = int(input())
a = n // 10
b = n % 10
print((a + b) ** 2)